620 STATISTICS AND PROBABILITY
At a level of significance of 5%, use the
Wilcoxon signed-rank test to test the null
hypothesis that the average value for the
method of analysis used is 150 ppm.
⎡
⎢
⎣
H 0 :s=150,H 1 :s=150,
T= 38 .From Table 63.4,
T≤40, hence alternative
hypothesisH 1 is accepted
⎤
⎥
⎦
- A paint supplier claims that a new additive
will reduce the drying time of their acrylic
paint. To test his claim, 12 pieces of wood
are painted, one half of each piece with paint
containing the regular additive and the other
half with paint containing the new additive.
The drying time (in hours) were measured as
follows:
New
additive 4.5 5.5 3.9 3.6 4.1 6.3
Regular
additive 4.7 5.9 3.9 3.8 4.4 6.5
New
additive 5.9 6.7 5.1 3.6 4.0 3.0
Regular
additive 6.9 6.5 5.3 3.6 3.9 3.9
Use the Wilcoxon signed-rank test at a sig-
nificance level of 5% to test the hypothesis
that there is no difference, on average, in the
drying times of the new and regular additive
paints.
⎡ ⎢ ⎢ ⎢ ⎢ ⎣
H 0 :N=R,H 1 :N=R,T= 5
From Table 63.4, withn= 10
(since two differences are zero),
T≤8, Hence there is a
significant difference in the
drying times
⎤ ⎥ ⎥ ⎥ ⎥ ⎦
63.6 The Mann-Whitney test
As long as the sample sizes are not too large, for
tests involving two samples, the Mann-Whitney test
is easy to apply, is powerful and is widely used.
Procedure
(i) State for the data the null and alternative
hypotheses,H 0 andH 1.
(ii) Know whether the stated significance level,α,
is for a one-tailed or a two-tailed test (see (ii)
in the procedure for the sign test on page 614).
(iii) Arrange all the data in ascending order whilst
retaining their separate identities.
(iv) If the data is now a mixture of, say,A’s andB’s,
write under each letterAthe number ofB’s that
precede it in the sequence (or vice-versa).
(v) Add together the numbers obtained from
(iv) and denote total byU.Uis defined as
whichever type of count would be expected to
be smallest whenH 1 is true.
(vi) Use Table 63.5 on pages 622 and 623 for given
values ofn 1 andn 2 , andα 1 orα 2 to read
the critical region ofU. For example, if, say,
n 1 =10 andn 2 =16 andα 2 =5%, then from
Table 63.5,U≤42. IfUin part (v) is greater
than 42 we accept the null hypothesisH 0 , and
ifUis equal or less than 42, we accept the
alternative hypothesisH 1.
The procedure for the Mann-Whitney test is demon-
strated in the following problems.
Problem 11. 10 British cars and 8 non-British
cars are compared for faults during their first
10 000 miles of use. The percentage of cars of
each type developing faults were as follows:
Non-British
cars,P 5 8 14 10 15
British
cars,Q 18 9 25 6 21
Non-British
cars,P 712 4
British
cars,Q 20 28 11 16 34
Use the Mann-Whitney test, at a level of sig-
nificance of 1%, to test whether non-British
cars have better average reliability than British
models.
Using the above procedure:
(i) The hypotheses are:
H 0 : Equal proportions of British and non-
British cars have breakdowns.
H 1 : A higher proportion of British cars have
breakdowns.