3.3 The One-Sided Laplace Transform 181
0 2 4
− 1
−0.5
0
0.5
1
t
y(t)=cos(10t) exp(−t)u(t)
− 2 0 2
− 10
− 5
0
5
10
σ
jΩ
(a)
(b)
x(t)=exp(−t)u(t)
0 2 4
0
0.5
1
− 2 0 2
− 1
−0.5
0
0.5
1
σ
jΩ
FIGURE 3.7
Poles and zeros of the Laplace transform of (a) causal signalx(t)=e−tu(t)and of (b) causal decaying signal
y(t)=e−tcos( 10 t)u(t).
nExample 3.5
In statistical signal processing, the autocorrelation functionc(τ)of a random signal describes the
correlation that exists between the random signalx(t)and shifted versions of it,x(t+τ)andx(t−
τ)for shifts−∞< τ <∞. Clearly,c(τ)is two-sided (i.e., nonzero for both positive and negative
values ofτ) and symmetric. Its two-sided Laplace transform is related to the power spectrum of
the signalx(t). Letc(t)=e−a|t|, wherea>0 (we replaced theτvariable fortfor convenience). Find
its Laplace transform. Determine if it would be possible to compute|C()|^2 , which is called the
power spectrum of the random signalx(t).
Solution
The autocorrelation can be expressed as
c(t)=c(t)u(t)+c(t)u(−t)
=cc(t)+cac(t)
wherecc(t)is the causal component andcac(t)the anti-causal component ofc(t). The Laplace
transform ofc(t)is then given by
C(s)=L[cc(t)u(t)]+L[cac(−t)u(t)](−s)