270 C H A P T E R 4: Frequency Analysis: The Fourier Series
nExample 4.11
Consider the train of pulses in Example 4.5. Determine how many Fourier coefficients are necessary
to get a representation containing 97% of the power of the periodic signal.
Solution
The desired 97% of the power ofx(t)is
0.97
1
T 0
∫
T 0
x^2 (t)dt=0.97
0.25∫
−0.25
4 dt=1.94
and so we need to find an integerNsuch that
∑N
k=−N
|Xk|^2 =
∑N
k=−N
∣
∣
∣
∣
sin(πk/ 2 )
(πk/ 2 )
∣
∣
∣
∣
2
=1.94
The value ofNis found by trial and error, adding consecutive values of the magnitude squared
of Fourier coefficients. Using MATLAB, it is found that forN=5 (dc and 5 harmonics) the
Fourier series approximation has a power of 1.93. Thus, 11 Fourier coefficients give a very good
approximation to the periodic train of pulses, with about 97% of the signal power. n
4.8 Time and Frequency Shifting................................................................
Time shifting and frequency shifting are duals of each other.
n Time-shifting: A periodic signalx(t), of periodT 0 , remains periodic of the same period when shifted in
time. IfXkare the Fourier coefficients ofx(t), the Fourier coefficients forx(t−t 0 )are
{
Xke−jk^0 t^0 =|Xk|ej(∠Xk−k^0 t^0 )
}
(4.27)
That is, only a change in phase is caused by the time shift. The magnitude spectrum remains the same.
n Frequency-shifting: When a periodic signalx(t), of periodT 0 , modulates a complex exponentialej^1 t:
n The modulated signalx(t)ej^1 tis periodic of periodT 0 if 1 =M 0 for an integerM≥ 1.
n The Fourier coefficientsXkare shifted to frequenciesk 0 + 1.
n The modulated signal is real-valued by multiplyingx(t)bycos( 1 t).
If we delay or advance in time a periodic signal, the resulting signal is periodic of the same period.
Only a change in the phase of the coefficients occurs to accommodate for the shift. Indeed, if
x(t)=
∑
k
Xkejk^0 t