322 CHAPTER 5: Frequency Analysis: The Fourier Transform
SolutionThe energy of the pulse isE=2 (the area under the pulse). But according to Parseval’s result the
energy computed in the frequency domain is given by1
2 π∫∞
−∞(
2 sin()
) 2
d=Exsince 2 sin()/=P()=F(p(t)). ReplacingEx, we obtain the interesting and not obvious result
∫∞−∞(
sin()
) 2
d=πThis is one more way to computeπ! n5.6.4 Symmetry of Spectral Representations........................................
Now that the Fourier representation of aperiodic and periodic signals is unified, we can think of
just one spectrum that accommodates both finite-energy as well as infinite-energy signals. The word
spectrumis loosely used to mean different aspects of the frequency representation. In the following
we provide definitions and the symmetry characteristic of the spectrum of real-valued signals.IfX()is the Fourier transform of a real-valued signalx(t), periodic or aperiodic, the magnitude|X()|is an
even function of:|X()|=|X(−)| (5.16)and the phase∠X()is an odd function of:∠X()=−∠X(−) (5.17)We then have:
Magnitude spectrum: |X()|versus
Phase spectrum: ∠X()versus
Energy/power spectrum: |X()|^2 versusTo show this, consider the inverse Fourier transform of a real-valued signalx(t),x(t)=∫∞
−∞X()ejtdwhich, because of being real, is identical tox∗(t)=∫∞
−∞X∗()e−jtd=∫∞
−∞X∗(−)ejtd