322 CHAPTER 5: Frequency Analysis: The Fourier Transform
Solution
The energy of the pulse isE=2 (the area under the pulse). But according to Parseval’s result the
energy computed in the frequency domain is given by
1
2 π
∫∞
−∞
(
2 sin()
) 2
d=Ex
since 2 sin()/=P()=F(p(t)). ReplacingEx, we obtain the interesting and not obvious result
∫∞
−∞
(
sin()
) 2
d=π
This is one more way to computeπ! n
5.6.4 Symmetry of Spectral Representations........................................
Now that the Fourier representation of aperiodic and periodic signals is unified, we can think of
just one spectrum that accommodates both finite-energy as well as infinite-energy signals. The word
spectrumis loosely used to mean different aspects of the frequency representation. In the following
we provide definitions and the symmetry characteristic of the spectrum of real-valued signals.
IfX()is the Fourier transform of a real-valued signalx(t), periodic or aperiodic, the magnitude|X()|is an
even function of:
|X()|=|X(−)| (5.16)
and the phase∠X()is an odd function of:
∠X()=−∠X(−) (5.17)
We then have:
Magnitude spectrum: |X()|versus
Phase spectrum: ∠X()versus
Energy/power spectrum: |X()|^2 versus
To show this, consider the inverse Fourier transform of a real-valued signalx(t),
x(t)=
∫∞
−∞
X()ejtd
which, because of being real, is identical to
x∗(t)=
∫∞
−∞
X∗()e−jtd=
∫∞
−∞
X∗(−)ejtd