9.4 One-Sided Z-Transform 525
The Z-transform pairs of a cosine and a sine are, respectively,
cos(ω 0 n)u[n] ⇔
z(z−cos(ω 0 ))
(z−ejω^0 )(z−e−jω^0 )
ROC :|z|> 1 (9.14)
sin(ω 0 n)u[n] ⇔
zsin(ω 0 )
(z−ejω^0 )(z−e−jω^0 )
ROC :|z|> 1 (9.15)
The Z-transforms for these sinusoids have identical poles 1 e±jω^0 , but different zeros. The frequency of the
sinusoid increases from the lowest(ω 0 =0 rad)to the highest(ω 0 =πrad)) as the poles move along the unit
circle from 1 to− 1 in its lower and upper parts.
Consider then the signalx[n]=rncos(ω 0 n+θ)u[n], which is a combination of the above cases. As
before, the signal is expressed as a linear combination
x[n]=
[
ejθ(rejω^0 )n
2
+
e−jθ(re−jω^0 )n
2
]
u[n]
and it can be shown that its Z-transform is
X(z)=
z(zcos(θ)−rcos(ω 0 −θ))
(z−rejω^0 )(z−re−jω^0 )
(9.16)
The Z-transform of a sinusoid is a special case of the above (i.e., whenr=1). It also becomes clear
that as the value ofrdecreases toward zero, the exponential in the signal decays faster, and that
wheneverr>1, the exponential in the signal grows making the signal unbound.
The Z-transform pair
rncos(ω 0 n+θ)u[n] ⇔
z(zcos(θ)−rcos(ω 0 −θ))
(z−rejω^0 )(z−re−jω^0 )
(9.17)
shows how complex conjugate pairs of poles inside the unit circle represent the damping indicated by the
radiusrand the frequency given byω 0 in radians.
Double poles are related to the derivative ofX(z)or to the multiplication of the signal byn. If
X(z)=
∑∞
n= 0
x[n]z−n
its derivative with respect tozis
dX(z)
dz
=
∑∞
n= 0
x[n]
dz−n
dz
=−z−^1
∑∞
n= 0
nx[n]z−n