Physical Chemistry , 1st ed.

ln  Q N C C  (^) C ln  Q N D D  (^) D ln  Q N A A  (^) A ln  Q N B B  (^) B  0 In the next step, we will do t ...

Equation 18.62 shows that statistical thermodynamics can calculate temperature- dependent equilibrium constants from partition f ...

constants of reactions knowing little other than the energy levels of the equi- librium species. This is a powerful predictive t ...

can be treated statistically, why not apply statistical thermodynamics to crys- tals, whose atomic contributions to the properti ...

low temperatures, predicting a lower heat capacity than is measured experi- mentally. In fact, using the mathematics of limits, ...

were greater than (^) D,g( ) 0. The frequency distribution function in equation 18.68 can be substituted into the statistical th ...

capacity of crystals is considered more successful. Once again, because absolute temperature and Dalways appear together as a r ...

18.2 Nuclear and Electronic Partition Functions 18.1.Using a table of nuclear spin states, determine qnucfor (a)^12 C atoms, (b) ...

18.27.Use statistical thermodynamics to determine H°(25°C) and S°(25°C) for the reaction H 2 (g) D 2 (g) →2HD (g) You should ...

19 651651 W HY DO GASES BEHAVE THE WAY they do? In some of the previous chapters, we have used gases as examples with an implici ...

In this chapter on kinetic theory, we will consider the origin of the pressure of gases. We will find that the speeds of gas par ...

some initial velocity labeled vi, and after the collision it has some final veloc- ity vf. The change in the velocity, which is ...

Since the mass of the particle is constant, it can be removed from the integral, which is easily evaluated to get Favg tim 1 e ...

We recognize that pressure is defined as force per unit area. If we are moving in the xdimension, then the wall we are colliding ...

Solving, we find that vavg 1282  m s  or more than 1 km per second. This is a substantial velocity in terms of per- sonal exp ...

ticular gas particle; it could be anything. This does not imply that all possible velocities will exist in any gas sample at equ ...

Canceling all the units but kelvins and solving for T: T264 K The appropriate units for each variable should be used so that ev ...

 [g x v (v x x)]g y(vy) gz(vz)  [ v ( x v)]   [g x v (v x x)]g y(vy) gz(vz)  [ ( v v)]  v v x  (19.18) The righ ...

dimensions, we would get the same conclusions for yand z, and so we also have two other relationships with the same constant K: ...

Using the form ofgxin equation 19.24, this means that   vx Ae(1/2)Kvx 2 dvx 1 We can use the table of integrals in Appendi ...