where the S(products) and S(reactants) represent the absolute entropy of the
chemical species involved in the process. If standard conditions apply, every
entropy term can have a degree symbol ° appended:
rxnS°
0
products
S°
0
reactants
S°
Changes in entropy for chemical processes can be considered using the above
Hess’s-law type of approach.
Example 3.7
Using the table in Appendix 2, determine the change in entropy for the fol-
lowing chemical reaction occurring at standard pressure and the stated tem-
perature:
2H 2 (g) + O 2 (g) →2H 2 O ()
Solution
From the table,S°[H 2 (g)] 130.7 J/molK,S°[O 2 (g)] 205.1 J/molK, and
S°[H 2 O, ()] 69.91 J/molK. Keeping in mind that the balanced chemical
reaction gives molar ratios of reactants and products, equation 3.27 yields
rxnS°[2 69.91] [2 130.7 205.1] J/K
0
products
S°
0
reactants
S°
where the entropies of the products and reactants are labeled. The mol units
cancel because we are including the stoichiometry explicitly: 2 mol H 2 O as
products, and 2 mol H 2 and 1 mol O 2 as reactants. Evaluating:
rxnS°326.7 J/K
That is, during the course of the reaction, the entropy is decreasing by 326.7 J/K.
Does this make sense, in terms of entropy as a measure of the number of
accessible states? The balanced chemical reaction is showing 3 moles of gas
reacting to make 2 moles of liquid. It can be argued that a condensed phase
will have fewer accessible states than a gas will, and the actual number of
molecules is decreasing. Therefore, a decrease in entropy is understandable.
As with H, there are many times when Sneeds to be determined for a
process that occurs at different temperatures and pressures. Equation 3.18, or
82 CHAPTER 3 The Second and Third Laws of Thermodynamics
S
Total entropy of reactants
rxnS Sproducts Sreactants
Total entropy of products
Figure 3.8 Entropy can change for a reaction, just like enthalpy can change. In this case, the
entropy of the products is less than that of the reactants, so the rxnSis negative.