Calculus: Analytic Geometry and Calculus, with Vectors

(lu) #1
12.5 Taylor formulas with remainders 633

Integrating by parts with

u=f'(t) dv=dt


du = f"(t) dt, v = - (x - t)

gives


or

f(x) = f(a) + [-f'(t)(x - t)la -+- I Zf"(t) (x 1t)dt


(12.52) f(x) = f(a) + la (x - a) +

J

f" (t) (x 1 t)dt.
aa

Another integration by parts with

u = f' (t) dv =(x 1 t)dt

du = f" (t) dt, v = - (x - t) 2
2!
gives

f(x) = f(a) (x - a) (x - a)2 + / z f( )(t) (x2it) dt.

One more integration by parts gives the result of putting n = 3 in the
formula

(12.53) f(x) = f(a) + -i-a) (x - a) + f-2 a) (x - a)2

(") a
+. .. +f
n

(x - a)" + Rn(x),

where

(12.54) Rn(x) = 1 f t)^ dt,

and further integrations by parts give the results when n = 4, 5, 6,.
The formula (12.53) is a Taylor formula with remainder R,(x). The right
member of (12.54) is the integral form of the remainder. In some cases,
(12.54) and other remainder formulas can be used to determine values of
x for which

(12.55) lim R (x) = 0.
n-»

For such values of x the Taylor formula

(12.56) f(x) = f(a) (x - a) +f' (a) (x - a)2 +
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