28 Time Dependent Perturbation Theory
We have used time independent perturbation theory to find the energy shifts of states and to find
the change in energy eigenstates in the presence of a small perturbation. We will now consider the
case of a perturbation that is time dependent. Such a perturbation can cause transitions between
energy eigenstates. We will calculate the rate of those transitions.
This material is covered inGasiorowicz Chapter 21,inCohen-Tannoudji et al. Chapter
XIII,and briefly in Griffiths Chapter 9.
28.1 General Time Dependent Perturbations
Assume that we solve the unperturbed energy eigenvalue problem exactly:H 0 φn=Enφn. Now we
add a perturbation that depends on time,V(t). Our problem is now inherently time dependent so
we go back to thetime dependent Schr ̈odinger equation.
(H 0 +V(t))ψ(t) =i ̄h
∂ψ(t)
∂t
We willexpandψin terms of the eigenfunctions:ψ(t) =
∑
k
ck(t)φke−iEkt/ ̄hwithck(t)e−iEkt/ ̄h=
〈φk|ψ(t)〉. The time dependent Schr ̈odinger equations is
∑
k
(H 0 +V(t))ck(t)e−iEkt/ ̄hφk = i ̄h
∑
k
∂ck(t)e−iEkt/ ̄h
∂t
φk
∑
k
ck(t)e−iEkt/ ̄h(Ek+V(t))φk =
∑
k
(
i ̄h
∂ck(t)
∂t
+Ekck(t)
)
e−iEkt/ ̄hφk
∑
k
V(t)ck(t)e−iEkt/ ̄hφk = i ̄h
∑
k
∂ck(t)
∂t
e−iEkt/ ̄hφk
Now dot〈φn|into this equation to get the time dependence of one coefficient.
∑
k
Vnk(t)ck(t)e−iEkt/ ̄h = i ̄h
∂cn(t)
∂t
e−iEnt/ ̄h
∂cn(t)
∂t
=
1
i ̄h
∑
k
Vnk(t)ck(t)ei(En−Ek)t/ ̄h
Assume that att= 0, we are in aninitial stateψ(t= 0) =φiand hence all the otherckare equal
to zero:ck=δki.
∂cn(t)
∂t
=
1
i ̄h
Vni(t)eiωnit+
∑
k 6 =i
Vnk(t)ck(t)eiωnkt