130_notes.dvi

(Frankie) #1

Define the4 by 4 matricesγμare by.


γi =

(

0 −iσi
iσi 0

)

γ 4 =

(

1 0

0 − 1

)

With this definition, the relativistic equation can be simplified a great deal
(
γμ



∂xμ

+

mc
̄h

)

ψ= 0

where the gamma matrices are given by


γ 1 =




0 0 0 −i
0 0 −i 0
0 i 0 0
i 0 0 0



 γ 2 =




0 0 0 − 1

0 0 1 0

0 1 0 0

−1 0 0 0




γ 3 =




0 0 −i 0
0 0 0 i
i 0 0 0
0 −i 0 0



 γ 4 =




1 0 0 0

0 1 0 0

0 0 −1 0

0 0 0 − 1




and they satisfy anti-commutation relations.

{γμ,γν}= 2δμν

In fact any set of matrices that satisfy the anti-commutation relations would yield equivalent physics
results, however, we will work in the above explicit representation of the gamma matrices.


Definingψ ̄=ψ†γ 4 ,
jμ=icψγ ̄μψ


satisfies the equation of a conserved 4-vector current



∂xμ

jμ= 0

and also transforms like a 4-vector. The fourth component of thevector shows that the probability
density isψ†ψ. This indicates that the normalization of the state includes all four components of
the Dirac spinors.


For non-relativistic electrons, the first two components of the Dirac spinor are large while the last
two are small.


ψ=

(

ψA
ψB

)

ψB≈

c
2 mc^2

~σ·

(

~p+

e
c

A~

)

ψA≈

pc
2 mc^2

ψA

We use this fact to write an approximate two-component equation derived from the Dirac equation
in the non-relativistic limit.
(
p^2
2 m



Ze^2
4 πr


p^4
8 m^3 c^2

+

Ze^2 L~·S~
8 πm^2 c^2 r^3

+

Ze^2 ̄h^2
8 m^2 c^2

δ^3 (~r)

)

ψ = E(NR)ψ
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