A Guidebook to Mechanism in Organic Chemistry

(Barry) #1
Reactions with Metals

form a carbon-carbon bond yielding the magnesium salt (XIV) of
a pinacol; subsequent acidification yields the free pinacol (XV):


R 2 C=0 R 2 C-0 R 2 C-0 R„C-OH
:Mg
R 2 C=0

/


Mg
R 2 C—O
(XIII)

RaC—O

)>Mg


(XIV)

RjC—OH
(XV)

This reaction is unusual in involving initial attack on oxygen rather
than carbon. Pinacol itself is Me 2 C(OH)-C(OH)Me 2 , but the name
has comeHrtb used generally for such tertiary-1,2-diols. The reac­
tion is most readily seen when sodium is dissolved, in the absence of
air, in ethereal solutions of aromatic ketones, the blue, paramagnetic
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radical-ion of the sodium ketyl, Ar 2 C—O*—>Ar 2 C—O, then being
in equilibrium with the dianion of the corresponding pinacol:
Ar 2 C—O^9
Ar 2 C—O^9
(b) Sodium and esters: Sodium will donate an electron to an ester
to yield the radical-ion (XVI), two molecules of which unite (XVII)
(cf. pinacol formation above) and expel EtO® to^irid the a-diketone
(XVIII). Further electron donation by sodium yields the diradica^ion
(XIX), which again forms a carbon-carbon bond (XX). Acidification
yields the a-hydroxyketone or acyloin (XXI):

2R—C—OEt


I
2Na- R—C—OEt

R—C—OEt

(XVI)

R-C^OEt
R—C-^OEt

&
(XVII)

o
II
R—C
I
R—C
II
O (XVIII)

o
II
R—C
I
R»-CH
I
OH
(XXI)

OH O
R—Cm H© R—C

2Na-
G

R—C
I
OH

R—C

i.
(XX)

o
I
R—C-
I
R—C-

A.
(XIX)
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