Mathematical Foundation of Computer Science

(Chris Devlin) #1
DHARM

PROPOSITIONAL LOGIC 125


Since we find the conclusion; therefore conclusion is valid at stage 3. Thus, conclusion is
valid at stage 2 at hence old conclusion must be valid.
IV. Rule of Indirect Proof


Example 5.21. Show that



  1. A /∴ B ∨ ~ B
    Sol. In order to show that a conclusion follows logically from the premise/s, we assume that
    the conclusion is false. Take negation of the conclusion as the additional premise and start
    deduction. If we obtain a contradiction (s.t. R ∧ ~ R where, R is any formula) then, the negation
    of conclusion is true doesn’t hold simultaneously with the premises being true. Thus negation
    of conclusion is false. Therefore, conclusion is true whenever premises are true. Hence conclu-
    sion follows logically from the premises. Such procedure of deduction is known as Rule of
    Indirect Proof (IP) or Method of Contradiction or Reductio Ad Absurdum.
    Therefore,

  2. A/∴ B ∨ ~ B

  3. ~ (B ∨ ~ B) IP

  4. ~ B ∧ ~ ~ B 2, Dem
    Since, we get a contradiction, so deduction process stops. Therefore, the assumption
    negation of conclusion is wrong. Hence, conclusion must be true.


Example 5.22. Show ~ (H ∨ J) follows logically from (H → I) ∧ (J → K), (I ∨ K) → L and ~ L.
Sol.



  1. (H → I) ∧ (J → K)

  2. (I ∨ K) → L

  3. ~ L /∴ ~ (H ∨ J)

  4. ~ (I ∨ K) 2 & 3, MT

  5. ~ I ∧ ~ K 4, Dem

  6. ~ I 5, Simp

  7. ~ K ∧ ~ I 5, Comm

  8. ~ K 7, Simp

  9. H → I 1, Simp

  10. ~ H 9 & 6, MT

  11. (J → K) ∧ (H → I) 1, Comm

  12. J → K 11, Simp

  13. ~ J 12 & 8, MT

  14. ~ H ∧ ~ J 13 & 10, Conj

  15. ~ (H ∨ J) 14, DeM
    There is alternate method to reach the conclusion using Indirect Proof
    Since we have 1 – 3 premises; so

  16. ~ ~ ((H ∨ J) Indirect Proof (IP)

  17. H ∨ J 4, DeM

  18. I ∨ K 1 & 5, CD

  19. L 2 & 6, MP

  20. L ∧ ~ L 7 & 3, Conj

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