Power Plant Engineering

200 POWER PLANT ENGINEERING pressure cylinder normally uses double flow). This type of unit is completely balanced against the e ...

STEAM TURBINE 201 remains the same. The steam at condenser pressure or exhaust pressure enters the blade and comes out at the sa ...

202 POWER PLANT ENGINEERING the leaving loss is also very high. It is therefore essential to incorporate some improvements in th ...

STEAM TURBINE 203 mounted on the same shaft and the blades are attached on the rotor. The rotor (i.e. disc) may be keyed to the ...

204 POWER PLANT ENGINEERING Nozzle Moving blades Re-entry passage Steam re-entry Fig. 6.9. Flow of Steam on Blades. The whole ex ...

STEAM TURBINE 205 In the first set of nozzles, there is some decrease in pressure which gives some kinetic energy to the steam a ...

206 POWER PLANT ENGINEERING As the pressure falls, the specific volume increases and hence in practice, the height of blades is ...

STEAM TURBINE 207 6.11 Capability The capability of steam turbine is the maximum continuous out put for a clean turbine operatin ...

208 POWER PLANT ENGINEERING (iv) Variation in temperature of feed water. (v) The varying condition of cleanliness of heat absorb ...

STEAM TURBINE 209 sion. Generator losses appearing as heat must be constantly removed to avoid damaging the windings. Large gene ...

210 POWER PLANT ENGINEERING Now, Vb = 144 m/s ; V 1 = 144 = 300 m/s 0.48 V^2 /2 × 10^3 = Isentropic heat drop × Nozzle efficienc ...

STEAM TURBINE 211 Area of flow, A = πDh = 3.14 * 0.917 * 10 100 = 0.288 m^2 Now from steam table, for steam dry and saturated at ...

212 POWER PLANT ENGINEERING Vb Vt 1 A E CD Vr 0 Vr 1 V 1 α φ= 31.5° B θ= 29.5 V = V 0 a 0 Va 1 m = A ×^1 V V a s = πDh ×^1 V V a ...

STEAM TURBINE 213 1 V V b = cos^20 2 ° = 0.47 For the present problem = Vb = 0.6 × 0.47 × V 1 = 282 m/s α = 20°, V 1 =1000 m/s w ...

214 POWER PLANT ENGINEERING Steam flow rate through blades = 0.92 × 16500 3600 = 4.216 kg/s Power output = 3.31 = m × Vb ×^10 (V ...

STEAM TURBINE 215 Vb A E C D Vr 0 Vr 1 V 1 Va 0 V^0 Va 1 Vr 0 Vt 1 B 35° 20° 20° 35° F Power = m × Vb ×^10 (V V ) 1000 tt− kW = ...

216 POWER PLANT ENGINEERING 3.Steam at pressure of 30.23 bar and 400°C temperature is supplied to a steam turbine and is exhaust ...

Chapter 7Chapter 7Chapter 7Chapter 7Chapter 7 Fuels and CombustionFuels and CombustionFuels and CombustionFuels and CombustionFu ...

218 POWER PLANT ENGINEERING There are many ways of classifying coal according to its chemical and physical properties The most a ...

FUELS AND COMBUSTION 219 7.3 Coal Analysis There are two types of coal analysis: proximate and ultimate, both done on a mass per ...