NON-CONVENTIONAL ENERGY RESOURCES AND UTILISATION 117
Axial thrust (Fx) in newtons Fx max = (π/9) ρD^2 Vi^2 = π/9 (1.226 × 120^2 × 10^2 )
= 616,255 N.
Example 12. A 10 m/s wind is at 1 standard atmosphere and 15°C. Calculate:- The total power density in the wind stream.
- The maximum obtainable power density.
- A reasonably obtainable power density.
- Total power produced if the turbine diameter is 120 m.
Solution. The air density,
ρ =P
RT
= (1.01325 × 10^5 )/[287 (15 + 273)] = 1.226 kg/m^3.- Total power density
ρtotal
A=32ρVi= 1.226 × (10)^3 /2 = 613 W/m^3- Maximum power density
max
Aρ
=8
27ρVi^3= (8/27) × 1.226 × (10)^3 = 363 W/m^3.- Assuming ηηηηη = 40%
Actual power density,
P
A= 0.4 wtP
A
= 0.4 × 613 = 245 W/m^3.- Total power produced,
P =P
A
24πD= 0.245 × π(120)^2 /4 = 2770 kW.
Example 13. A 10 metre diameter rotor has 30 blades, each 0.25 metre wide. Calculate its
solidity.
Solution. Solidity = [(No. of blade × width)/(π × dia of rotor)] × 100 in %
Given that
Number of blade = 30
Width = 0.25 m
Diameter of rotor = 10 m