HYDRO-ELECTRIC POWER PLANTS 371
Pa
A
H 0
H
pa
h
B
C
D
E
hd
Fig. 11.26
Ea = Eb = H + hd +
pa
ρ
Ec = h +hd +
2
2
Vc
g
+ c
p
ρ
Ed =
2
2
Vd
g
+ d
p
ρ
.
WZ (work done per kg of water passing through the turbine) = Eb – Ec = Eb – (Ed + hf)
where Ec = Ed + hf where h is the head lost by water passing through the draft tube (friction and
other losses).
= d a
p
Hh
++
ρ
2
2
dd
f
Vp
h
g
++
ρ
=
2
2
H Vd
g
−
+ hd ppad
+−
ρρ
- hf
The pressure at the point D and E must be same.
∴ d
p
ρ
= a
p
ρ
+ hd
Substituting this value in the above equation, we get
W 2 =
2
2
H Vd
g
−
- hf
= H –
2
2
Vd
g
in hf is taken as zero ...(b)