3.30 I FUNDAMENTALS OF BUSINESS MATHEMATICS AND STATISTICS
Calculus
Theorem. If y = f(z) and z = φ (x) then dy dy dzdx dz dx=. (proof is not shown at present)
Corr. If u = f(v), v = φ (w), w = ψ (x) then du du dv dwdx dv dw dx=..
Example 62 : To find dydx for y = 2z^2 + 1, z = 4x – 2
Solution:
Now ddzy=4z and ddxz=^4
dy dy dz. 4z. 4 16z 16(4x 2) 64x 32.
dx dz dx= = = = − = −
Rule 1.If y = ax + b, to find dydx. Let y = z, and z = ax + b.
So y = f (z) and z = f (x)
∴ ddx dz dxy dy dz=. 1=. (a. 1 + 0) = a
Rule. 2. If y = (ax + b)n, to find dydx Let y = zn and z = ax + b
Now dydz=n.zn 1− and dzdx=a
∴ dy dy dzdx dz dx=. nz= n 1− a = na (ax + b)n – 1
Example 63 : If {y = (2x + 5)^4 ] Let y = z^4 , where z = 2x + 5.
Now dzdy=4z ,^3 dxdz=^2
Now dx dz dxdy dy dz=. 4z. 2 4.2 2x 5 8 2x 5=^3 = ( + )^3 = ( + )^3
Rule 3.If y = log u (u is a function of x), then to find dydx; dy dy dudx du dx=.