1.12 I FUNDAMENTALS OF BUSINESS MATHEMATICS AND STATISTICS
Arithmetic
FEW FORMULAE :
Compound Interest may be paid half-yearly, quarterly, monthly instead of a year. In these cases difference
in formulae are shown below :
(Taken P = principal, A = amount, T = total interest, i = interest on Re. 1 for 1 year, n = number of years.)
Time Amount I = A – P
(i) Annual A= P(1 + I)n I = P {(1 + i)n –1}
(ii) Half-Yearly
i 2n
A P 1=^ + 2
i^2 n
I P 1 2 1
(^)
= + −
(^)
(iii) Quarterly
i 4n
A P 1=^ + 4
i 4n
I P 1 4 1
(^)
= + −
(^)
In general if C.I. is paid p times in a year, then
i pn
A P 1=^ +p.
i.e. : Let P = ` 1000, r = 5% i.e., i = 0.05, n = 24 yrs.
If interest is payable yearly the A = 1000 (1 + 0.5)^24
If int. is payable half-yearly the A =
0.05 2 24
1000 1 2
×
- (^)
If int. is payable quarterly then A =
0.05 4 24
1000 1 4
×
- (^)
Note. or r = 100 I = interest per hundred.
If r = 6% then If, however i = 0.02 then, r = 100 × 0.02 = 2%.
SOLVED EXAMPLES. (using log tables)
[To find C.I.]
Example 22 : Find the compound interest on1,000 for 4 years at 5% p.a. Here P =
1000, n = 4, i = 0.05, A =?
We have A = P (1 + i)n
A = 1000 (1+ 0.05)^4
Or log A = log 1000 + 4log (1 + 0.05) = 3 + 4 log (1. 05) = 3 + 4 (0.0212) = 3 + 0.0848 = 3.0848
A = antilog 3.0848 = 1215
C.I. =1215 –
1000 = ` 215
[To find time]
Example 23 : In what time will a sum of money double itself at 5% p.a. C.I.
Here, P = P, A = 2P, i = 0.05, n =?