2.36 I FUNDAMENTALS OF BUSINESS MATHEMATICS AND STATISTICS
Algebra
Example 48 : Simplify
a b 2 b c 2 c a 2
a b c 4
(x ) .(x ) .(x )
(x ,x ,x )
+ + +
Solution : =
a b 2 b c 2 c a 2
a b c 4
(x ) .(x ) .(x )
(x ,x ,x )
+ + +
2a 2b 2b 2c 2c 2a m n mn
a b c 4
x .x .x (since (a ) a )
(x ,x ,x )
+ + +
= =
2a 2b 2b 2c 2c 2a m n m n
a b c 4
x (a a a )
(x )
+ + + + + +
= + + × =
4 a 4b 4c
4a 4b 4c
x 1
x
+ +
= + + =
Example 49 : Find the value of
7 5^34732
8 35 5 3^183
x x x y
x y x− (x )
×
Solution : Now ( )
(^4) 7 5 (^3732)
(^835) 5 3 1/8^3
x x x y
x y x− x
= ×
(^4) 7 5 7 3 3
3 35 8
(^4) 7 5 73 3 2 2
3 5 38 5 5 3/8 3/8
x x x y x x y
x y x x x .y x
- = − × = −
=[x^4 7 5 7 5 8 8+^3 +3 3 3 3− + − ][y ] xy.2 1− =
Example 50 : If m a ,n a anda [m n ]= x = y^2 = y x z Prove that xyz = 1
Solution :
m a= x m a ,n ay xy y n ax xy
[m n ] [a a ] ay x z = xy xyz = 2xyz=a (given) xyz 1^2
Example 51 : If x y,y z,z xa= b= c= prove that abc = 1.
Solution : We are given that
x y,....(i) y z,....(ii) z x,....(iii)a= b= c=
substituting the value of y from (i) in (ii)
(x ) z i.e., x za b= ab= ....(iv)
substituting the value of x from (iii) in (iv)
(z ) z i.e. zc ab= abc=z
Equating powers on the same base we get abc = 1
abc = 1
- = − × = −