Putting all together, and usingδ(pb−pa) to carry out the integration overpb, we have
〈qb|U(tb−ta)|qa〉 =
∫
dpa
2 π ̄h
e−i(tb−ta)p
(^2) a/(2m ̄h)
eipa(qb−qa)/ ̄h
=
( m
2 πi(tb−ta) ̄h
)^12
exp
{
im(qb−qa)^2
2 ̄h(tb−ta)
}
(14.17)
The full significance of the exponential factor will become clear later. Here, we notice simply that
the quantity
q ̇=
qb−qa
tb−ta
(14.18)
is the velocity needed for a free particle in uniform motion departing from positionqaat timetato
reach position theqbat timetb. Its energyEis just its kinetic energy, and the associated actionS
are given by
E(qb,tb;qa,ta) =
m(qb−qa)^2
2(tb−ta)^2
S(qb,tb;qa,ta) =
m(qb−qa)^2
2(tb−ta)
(14.19)
For the free particle, the matrix elements of the evolution operator are given by
〈qb|U(tb−ta)|qa〉∼exp{iS(qb,tb;qa,ta)/ ̄h} (14.20)
Notice that for fixedqa,qbandtb−ta→0,Sis becomes very large, unlessqa∼qb. Astb−ta→0,
the evolution operator becomes local inqand tends towardsδ(qb−qa).
14.4 Derivation of the path integral
We now seek a formula for〈qb|U(tb−ta)|qa〉which will be valid for a general time-independent
HamiltonianH(Q,P). It is convenient to begin by dividing the time intervaltb−ta>0 intoN
consecutive segments of equal lengthε= (tb−ta)/N. Using the multiplicative property of the
exponential, we have
U(tb−ta) =U(ε)N (14.21)
Inserting N−1 times the identity operator, expressed as a completeness relation on position
eigenstates, we obtain,
〈qb|U(tb−ta)|qa〉=
(N− 1
∏
n=1
∫
R
dqn
) N
∏
n=1
〈qn|U(ε)|qn− 1 〉 (14.22)
where we have setq 0 ≡qaandqN≡qb. The remainingqnforn= 1,···,N−1 are integrated over
in this formula, as may be seen schematically on the Figure below.
WhenN→∞andε→0, we may expand the evolution operator in a power series inε,
U(ε) =I−i
ε
̄h
H+O(ε^2 ) (14.23)