TITLE.PM5

638 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 Mean effective pressure, pm : pm = Work done by the cycle Swept volume ...

GAS POWER CYCLES 639 dharm \M-therm\Th13-3.pm5 = 10035 10035 mc Tp() 32 −T 17.77 005 1822.3 897.3( ) = ×−1.^ = 0.6048 or 60.48%. ...

640 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 Consider 1 kg of air. Total heat supplied = Heat supplied during the op ...

GAS POWER CYCLES 641 dharm \M-therm\Th13-3.pm5 Putting the value of T 2 in eqn. (ii), we get T T r 3 1 β =()γ− 1 T 1 = T r 3 1 1 ...

642 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 Example 13.23. The swept volume of a diesel engine working on dual cycl ...

GAS POWER CYCLES 643 dharm \M-therm\Th13-3.pm5 Also during the compression operation 1-2, p 1 V 1 γ = p 2 V 2 γ or p p V V 2 1 1 ...

644 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 Initial pressure, p 1 = 1 bar Initial temperature, T 1 = 30 + 273 = 303 ...

GAS POWER CYCLES 645 dharm \M-therm\Th13-3.pm5 ∴ T 2 = T 1 × 2.408 = 303 × 2.408 = 729.6 K For the constant volume process 2-3, ...

646 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 +Example 13.26. In an engine working on Dual cycle, the temperature and ...

GAS POWER CYCLES 647 dharm \M-therm\Th13-3.pm5 For the constant volume process 2-3, p T p T 2 2 3 3 = ∴ T 3 = T 2 × p p 3 2 = 87 ...

648 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 ∴ pm =^1 113 1 45 21 () () rV pVVpV p rV pV prV c − cc−+ cccc −× − − − ...

GAS POWER CYCLES 649 dharm \M-therm\Th13-3.pm5 ∴ T 2 = 300 × 2.954 = 886.2 K p p v v 2 1 1 2 =F 1514 HG I KJ = γ (). ⇒ p 2 = 44. ...

650 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 Effect of variable specific heat, heat loss through cylinder walls, in ...

GAS POWER CYCLES 651 dharm \M-therm\Th13-3.pm5 For adiabatic compression process 1-2, p 1 V 1 γ = p 2 V 2 γ or p 2 = p 1. V V 1 ...

652 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 or T 5 = T^4 227 3286 .. 227 = = 1447.5 K or 1174.5°C Heat rejected dur ...

GAS POWER CYCLES 653 dharm \M-therm\Th13-3.pm5 Compression ratio, rc = 9 Expansion ratio, re = 5 Number of cycles/sec. = 8 Cylin ...

654 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-3.pm5 p 5 = p 4 × V V n 4 5 F HG I KJ = p 4 × 1357 () 5125 . ren (). = = 4.77 ...

GAS POWER CYCLES 655 dharm \M-therm\Th13-3.pm5 (iv)Power of the engine, P : Power of the engine, P = Work done per second = Work ...

656 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-4.pm5 (b) 2 1 p = C p = C s 4 (^3) Diesel 3 ′ Dual 3 ′′ Otto v = C 2 ′ 4 ′′ 4 ...

GAS POWER CYCLES 657 dharm \M-therm\Th13-4.pm5 — For the maximum pressure the points 3 and 3′ must lie on a constant pressure li ...