TITLE.PM5

678 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-5.pm5 T s 4 ′ 4 3 2 ′ 2 1 10 5 7 ′ 7 6 9 9 ′ 8 p^2 px p^1 Fig. 13.51. T-s dia ...

GAS POWER CYCLES 679 dharm \M-therm\Th13-5.pm5 13.10.8.Gas turbine fuels The various fuels used in gas turbines are enumerated a ...

680 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 Example 13.32. Air enters the compressor of a gas turbine plant operati ...

GAS POWER CYCLES 681 dharm \M-therm\Th13-6.pm5 ∴ ηcycle = Net Heat work added ()() () = −− − − mc T T mc T T mc T T p p p 34 21 ...

682 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 T s 2 1 3 Compressor 4 Turbine p = 1 bar 1 p = 4 bar^2 (ii)Power requir ...

GAS POWER CYCLES 683 dharm \M-therm\Th13-6.pm5 (ii)Heat supplied to air : For compression process 1-2, we have T T p p 2 1 2 1 ( ...

684 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 or, T 22 = T 1 T 3 or T 2 = TT 13 or, T 2 = 303 1073× = 570.2 K Now, Wt ...

GAS POWER CYCLES 685 dharm \M-therm\Th13-6.pm5 For the compression process 1-2, we have T T p p (^2) rp 1 2 1 (^11) 14 1 =F 625 ...

686 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 T (K) 1148 300 3 4 ′ 4 1 2 2 ′ 4bar 1bar s Fig. 13.57 ∴ T 2 = 300 × 1.4 ...

GAS POWER CYCLES 687 dharm \M-therm\Th13-6.pm5 For isentropic compression process 1-2 : T T p p 2 1 2 1 (^1) 14 1 62 14 1 =F HG ...

688 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 Example 13.40. The air enters the compressor of an open cycle constant ...

GAS POWER CYCLES 689 dharm \M-therm\Th13-6.pm5 ∴ C = m m a f + F H G I K (^1) J cp (T 3 – T 2 ′) ∴ 41800 = (90 + 1) × 1.0 × (T 3 ...

690 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 For compression process : cp = 1.005 kJ/kg K, γ = 1.4 For expansion pro ...

GAS POWER CYCLES 691 dharm \M-therm\Th13-6.pm5 Hence, Compressor work input, Wcompressor = cp (T 2 ′ – T 1 ) = 1.005 (529 – 288) ...

692 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 ηcompressor = 85%, ηturbine = 80%, ηcombustion = 85%. For air and gases ...

GAS POWER CYCLES 693 dharm \M-therm\Th13-6.pm5 Example 13.44. In a gas turbine the compressor is driven by the high pressure tur ...

694 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 power shaft. The isentropic efficiencies of compressor, and the H.P. an ...

GAS POWER CYCLES 695 dharm \M-therm\Th13-6.pm5 ∴ T 2 ′ = 502.5 288 0.82 − 288 = 549.6 K Wcompressor = cpa(T 2 ′ – T 1 ) = 1.005 ...

696 ENGINEERING THERMODYNAMICS dharm \M-therm\Th13-6.pm5 Again, for L.P. turbine : ηturbine = TT TT 45 45 ′− ′ ′− i.e., 0.85 = 6 ...

GAS POWER CYCLES 697 dharm \M-therm\Th13-6.pm5 T(K) 288 s 459 626 673 873 3 4 ′ 4 5 2 ′ 2 1 Fig. 13.64 Considering the isentropi ...