184 ENGINEERING THERMODYNAMICS
dharm
/M-therm/Th4-5.pm5
T 2
Ta
T 1
pa
p 1
p 2 2
p
v 12 = v v
a
1
(a)
vv 12 = p 2
a
p 1
s 1 s 2
s
T 1
T 2
T
1
2
(b)
Also
v
v
T
g Ts
sup 2 sup
2
2
2
=
∴
T
T
xv
s v
g
g
sup 2
2
1
2
=^1
...(4.69)
vg 2 and Ts 2 can be found from the steam tables corresponding to pressure p 2 and then Tsup 2
can be calculated by using the above equation. When the final condition is known, the change in all
other properties can be found easily.