184 ENGINEERING THERMODYNAMICS
dharm
/M-therm/Th4-5.pm5T 2
TaT 1pap 1p 2 2pv 12 = v va1(a)vv 12 = p 2a
p 1s 1 s 2
sT 1T 2T12(b)Also
v
vT
g Tssup 2 sup
22
2=∴T
Txv
s vg
gsup 2
21
2=^1
...(4.69)vg 2 and Ts 2 can be found from the steam tables corresponding to pressure p 2 and then Tsup 2can be calculated by using the above equation. When the final condition is known, the change in all
other properties can be found easily.