206 ENGINEERING THERMODYNAMICS
dharm
/M-therm/Th4-6.pm5
(^11)
2
2
p 1
p 2
T
s s
h
2 (wet)
2 (superheated)
p 2
p 1
1
1
Fig. 4.73. T-s diagram. Fig. 4.74. h-s diagram.
Now since Q = 0, and W = 0, then
h 1 + C^1
2
2
= h 2 + C^2
2
2
When the velocities C 1 and C 2 are small, or when C 1 is very nearly equal to C 2 , then the
K.E. terms may be neglected.
Then h 1 = h 2 ...(4.81)
i.e., For a throttling process :
Initial enthalpy = Final enthalpy.
The process is adiabatic but highly irreversible because of the eddying of the fluid around
the orifice at X. Between sections 1 and X the enthalpy drops and K.E. increases as the fluid
accelerates through the orifice. Between sections X and 2 the enthalpy increases as K.E. is destroyed
by fluid eddies.
During throttling pressure always falls.
The throttling process is used for the following purposes :
- To determine the dryness fraction of steam.
- To control the speed of the engine and turbine.
- To reduce the pressure and temperature of the liquid refrigerant from the condenser
condition to evaporator condition in a refrigeration system.
+Example 4.61. Steam at 18 bar is throttled to 1 bar and the temperature after throt-
tling is found to be 150°C. Calculate the initial dryness fraction of the steam.
Solution. Pressure of steam before throttling, p 1 = 18 bar
Pressure of steam after throttling = 1 bar
Temperature after throttling = 150°C
Initial dryness fraction, x 1 :
From superheat tables at 1 bar and 150°C, we have
h 2 = 2776.4 kJ/kg
Then for throttling, h 1 = h 2 = 2776.4
But h 1 = hxhf 11 + 1 fg