FIRST LAW OF THERMODYNAMICS 219
dharm
/M-therm/Th4-7.pm5
Answers
- (a) 2. (a) 3. (d) 4. (a) 5. (d) 6. (d) 7. (a)
- (d) 9. (a) 10. (c) 11. (e) 12. (a) 13. (d) 14. (b)
- (a) 16. (e) 17. (a) 18. (e) 19. (d) 20. (a) 21. (c)
- (b) 23. (e) 24. (d) 25. (b) 26. (a).
Theoretical Questions
- Define ‘internal energy’ and prove that it is a property of a system.
- Explain the First Law of Thermodynamics as referred to closed systems undergoing a cyclic change.
- State the First Law of Thermodynamics and prove that for a non-flow process, it leads to the energy
equation Q = ∆U + W. - What is the mechanical equivalent of heat? Write down its value when heat is expressed in kJ and work
is expressed in N-m. - What do you mean by “Perpetual motion machine of first kind-PMM 1”?
- Why only in constant pressure non-flow process, the enthalpy change is equal to heat transfer?
- Prove that the rate of change of heat interchange per unit change of volume when gas is compressed or
expanded is given by
γ
γ
−
− ×
n pdv
1 J.
- Write down the general energy equation for steady flow system and simplify when applied for the following
systems :
(i) Centrifugal water pump (ii) Reciprocating air compressor
(iii) Steam nozzle (iv) Steam turbine
(v) Gas turbine. - Explain clearly the difference between a non-flow and a steady flow process.
- For isothermal flow and non-flow steady processes, prove that
pdv v dp
1
2
1
2
zz=−.
Also state the assumptions made.
Unsolved Examples
Closed Systems
- In a cyclic process, heat transfers are + 14.7 kJ, – 25.2 kJ, – 3.56 kJ and + 31.5 kJ. What is the net work for
this cyclic process? [Ans. 17.34 kJ] - A domestic refrigerator is loaded with food and the door closed. During a certain period the machine
consumes 1 kWh of energy and the internal energy of the system drops by 5000 kJ. Find the net heat
transferred in the system. [Ans. – 8.6 MJ] - 1.5 kg of liquid having a constant specific heat of 2.5 kJ/kg°C is stirred in a well-insulated chamber causing
the temperature to rise by 15°C. Find :
(i) Change in internal energy, and
(ii) Work done for the process. [Ans. (i) 56.25 kJ, W = – 56.25 kJ] - A system is composed of a stone having a mass of 10 kg and a bucket containing 100 kg of water. Initially
the stone and water are at the same temperature, the stone then falls into the water. Determine ∆U, ∆KE,
∆PE, ∆Q and ∆W for the following cases :
(i) At the instant the stone is about to enter the water.