418 ENGINEERING THERMODYNAMICS
dharm
\M-therm\Th9-1.pm5
Again,
m
M
= n and Mcv = Cv
∴ U = nCvT ...(9.23)
Similarly, H = nCpT ...(9.24)
By the Gibbs-Dalton law,
U = Σ Ui and H = Σ Hi
∴ nCvT = Σ niCvi T and nCpT = Σ niCpiT
i.e., Cv =
n
n
i
∑ Cvi ...(9.25)
and Cp = n
n
i
∑ Cpi. ...(9.26)
9.6. Adiabatic Mixing of Perfect Gases
— Fig. 9.3 shows two gases A and B separated from each other in a closed vessel by a thin
diaphragm. If the diaphragm is removed or punctured then the gases mix and each
then occupies the total volume, behaving as if the other gas were not present. This
process is equivalent to a free expansion of each gas, and is irreversible. The process can
be simplified by the assumption that it is adiabatic ; this means that the vessel is
perfectly thermally insulated and there will therefore be an increase in entropy of the
system.
Diaphragm
Closed vessel
Gas A Gas B
mA nA
pA
TA VA
mB nB
pB
TB VB
Mixture of
gas A and gas B
m = m + mAB
p, T
V = V + VAB
n = n + nAB
Fig. 9.3
In a free expansion process, the internal energy initially is equal to the internal energy finally.
In this case, from eqn. (9.23),
U 1 = nACvA TA + nBCvBTB
and U 2 = (nACvA + nBCvB)T
If this result is extended to any number of gases, we have
U 1 = Σ niCviTi and U 2 = T Σ niCvi
Then U 1 = U 2
i.e., Σ niCviTi = T Σ niCvi
i.e., T =
Σ
Σ
nC T
nC
ivii
ivi
...(9.27)
— When two streams of fluid meet to form a common stream in steady flow, they give an-
other form of mixing (Fig. 9.4).