GASES AND VAPOUR MIXTURES 429
dharm
\M-therm\Th9-2.pm5xCO 2 =6
44
4
286
44
+=
01364
01428 01364.
..+
= 0.488. (Ans.)(ii)The equivalent molecular weight of the mixture, M :
M = 0.511 × 28 + 0.488 × 44 = 35.78 kg/kg mole. (Ans.)
(iii)The equivalent gas constant of the mixture, Rmix :Total mass, m = mN 2 + mCO 2 = 4 + 6 = 10 kg∴ Rmix =mR m R
mN 22 N + CO2 2CO=4 8 314
286 8 314
44
10×F
HGI
KJ
+×F
HGI
KJ..
Q R R
ML =
NMO
QP0= 0.232 kJ/kg K. (Ans.)
(iv)The partial pressures and partial volumes :
PN 2 = xN 2 × p = 0.511 × 4 = 2.044 bar. (Ans.)
PCO 2 = xCO 2 × p = 0.488 × 4 = 1.952 bar. (Ans.)VN 2 =
mRT
pNN (^22) =^4
8 314
28
293 10
410
3
5
×××
×
.
= 0.87 m^3. (Ans.)
VCO 2 =
mRT
p
CO 22 CO =^6
8 314
44
293 10
410
3
5
×××
×
.
= 0.83 m^3. (Ans.)
(v)The volume and density of the mixture :
Total volume of the mixture,
V =
mRT
p
mRT
p
NN
N
22
2
mRT
p
CO CO
CO
22
2
∴ V = 10 0 232 293 10
410
3
5
×××
×
. = 1.699 m (^3). (Ans.)
Density of the mixture,
ρmix = ρN 2 + ρCO 2 =
m
V
10
6991.
= 5.88 kg/m^3. (Ans.)
(vi)cp and cv of the mixture :
cpN 2 – cvN 2 = RN 2
∴ cvN 2 =
RN 2
γ− 1
8 314
28 1 4 1
.
(.− ) = 0.742 kJ/kg K.
and cpN 2 = 1.4 × 0.742 = 1.039 kJ/kg K