658 ENGINEERING THERMODYNAMICS
dharm
\M-therm\Th13-4.pm5
(i) 1-2—Heat rejection at constant pressure
(ii) 2-3—Adiabatic compression
(iii) 3-4—Addition of heat at constant volume
(iv) 4-1—Adiabatic expansion.
pv432 1AdiabaticAdiabaticFig. 13.30
Considering 1 kg of air.Compression ratio =
v
v2
3= αExpansion ratio = v
v1
4= r
Heat supplied at constant volume = cv(T 4 – T 3 )
Heat rejected = cv(T 1 – T 2 )
Work done = Heat supplied – heat rejected
= cv(T 4 – T 3 ) – cv(T 1 – T 2 )η = Work done
Heat supplied
=
−− −
−cT T cT T
cT Tv p
v()()
()43 12
43= 1 – γ. ()
()TT
TT12
43−
−
...(i)
During adiabatic compression 2-3,
T
Tv
v3
22
31
=F^1
HGI
KJ=−
−γ
()αγor T 3 = T 2 ()αγ−^1 ...(ii)
During constant pressure operation 1-2,
v
T
v
T1
12
2=