GAS POWER CYCLES 703
dharm
\M-therm\Th13-6.pm5
∴ T 7 = 898 –898 650
085F −
HGI
. KJ = 606 K
Also, T
Tp
p6
76
71
=
F
HGI
KJ−γ
γor p
p
T
T6
76
711 333
898 0 333
606= 482
F
HGI
KJ=F
HGI
KJ
=
−γ
γ...
Then,p
p8
99
482
=. = 1.86
Again, T
Tp
p8
98
9(^1) 1333 1
=F^133316
HG
I
KJ
γ− −
γ
()
.
1.86. 1.
∴ T 9 = T^8
16
898
- 16
= = 774 K
- 16
Also, ηturbine (L.P.) =TT
TT89
89−′
− ; 0.85 =898
898 774−′ 9
−T∴ T 9 ′ = 898 – 0.85 (898 – 774) = 792.6 K
∴ Net work output = cpg(T 8 – T 9 ′) × 0.95
= 1.15 (898 – 792.6) × 0.95 = 115.15 kJ/kg
Thermal ratio or effectiveness of heat exchanger,ε=−′
′− ′
= −
−TT
TT54 T
945 428
792.6 428i.e., 0.8 =
T 5 428
792 6 428
−. −
∴ T 5 = 0.8 (792.6 – 428) + 428 = 719.7 K
Now, Heat supplied = cpg(T 6 – T 5 ) + cpg(T 8 – T 7 ′)
= 1.15 (898 – 719.7) + 1.15 (898 – 650) = 490.2 kJ/kg
∴ ηthermal =
Net work output
Heat supplied
=
115 15
490 2.
.
= 0.235 or 23.5%. (Ans.)
(ii)Work ratio :
Gross work of the plant = Wturbine (H.P.) + Wturbine (L.P.)
= 285.5 +
115 15
095.
.
= 406.7 kJ/kg∴ Work ratio ==
Net work output
Gross work output115 15
406 7.
.
= 0.283. (Ans.)
(iii)Mass flow rate, m& :
Let the mass flow be m&, then
m& × 115.15 = 4500