722 ENGINEERING THERMODYNAMICSdharm
\M-therm\Th14-1.pm5T=- 5 + 273 = 268 K
3 T=
1000 + 273 = 1273 K1T=
25 + 273 = 298 K4 T=
25 + 273 = 298 K2W = (Q – Q )
= (Q – Q )12
43Heat pumpQ 3Q 4Q 1Q 2Heat engineFig. 14.3
975
1273
=30
2984
1×Q
Q∴ Q
Q4
1=^975
1273298
30× = 7.608. (Ans.)14.2.3. Reversed Brayton cycle
Fig. 14.4 shows a schematic diagram of an air refrigeration system working on reversed
Brayton cycle. Elements of this systems are :
- Compressor 2.Cooler (Heat exchanger)
- Expander 4. Refrigerator.
T
T
T
TAir
Cooling water cooler
Cold airVery cold
airExpanderRefrigeratorHot airWarm airCompressorFig. 14.4. Air refrigeration system.