722 ENGINEERING THERMODYNAMICS
dharm
\M-therm\Th14-1.pm5
T=
- 5 + 273 = 268 K
3 T=
1000 + 273 = 1273 K
1
T=
25 + 273 = 298 K
4 T=
25 + 273 = 298 K
2
W = (Q – Q )
= (Q – Q )
12
43
Heat pump
Q 3
Q 4
Q 1
Q 2
Heat engine
Fig. 14.3
975
1273
=
30
298
4
1
×Q
Q
∴ Q
Q
4
1
=^975
1273
298
30
× = 7.608. (Ans.)
14.2.3. Reversed Brayton cycle
Fig. 14.4 shows a schematic diagram of an air refrigeration system working on reversed
Brayton cycle. Elements of this systems are :
- Compressor 2.Cooler (Heat exchanger)
- Expander 4. Refrigerator.
T
T
T
T
Air
Cooling water cooler
Cold air
Very cold
air
Expander
Refrigerator
Hot air
Warm air
Compressor
Fig. 14.4. Air refrigeration system.