750 ENGINEERING THERMODYNAMICS
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\M-therm\Th14-3.pm5
(ii) The comparison between centrifugal and reciprocating compressors :
The comparison between centrifugal and reciprocating compressors is given in the table below :
S. No. Particulars Centrifugal compressor Reciprocating compressor
- Suitability Suitable for handling large Suitable for low discharges
volumes of air at low pressures of air at high pressure. - Operational speeds Usually high Low
- Air supply Continuous Pulsating
- Balancing Less vibrations Cyclic vibrations occur
- Lubrication system Generally simple lubrication Generally complicated
systems are required. - Quality of air delivered Air delivered is relatively Generally contaminated
more clean with oil. - Air compressor size Small for given discharge Large for same discharge
- Free air handled 2000-3000 m^3 /min 250-300 m^3 /min
- Delivery pressure Normally below 10 bar 500 to 800 bar
- Usual standard of compression Isentropic compression Isothermal compression
- Action of compressor Dynamic action Positive displacement.
(iii) Using property table of R-12 :
h 2 = 344.927 kJ/kg
h 4 = h 1 = 228.538 kJ/kg
(cp)v = 0.611 kJ/kg°C
s 2 = s 3
or 1.56323 = 1.5434 + 0.611 loge
t 3 273
30 273
+
+
L
N
M
O
Q
P
or t 3 = 39.995°C
h 3 = 363.575 + 0.611(39.995 – 30)
= 369.68 kJ/kg.
Rn/kg = h 2 – h 1 = 344.927 – 228.538
= 116.389 kJ/kg
W/kg = h 3 – h 2 = 369.68 – 344.927 = 24.753
C.O.P. = R
W
n=116.389
24.753
= 4.702. (Ans.)
Assuming cp for ice = 2.0935 kJ/kg°C
Heat to be removed to produce ice
=
2400
24 3600× [4.187(15 – 0) + 335 + 2.0935(0 – (– 5))]
= 11.3409 kJ/s = Work required, kJ/s (kW) × C.O.P.
∴ Work required (Power) =
11.3409
4.702
= 2.4 kW. (Ans.)
Example 14.17. A R-12 refrigerator works between the temperature limits of – 10°C and
- 30°C. The compressor employed is of 20 cm × 15 cm, twin cylinder, single-acting compressor
having a volumetric efficiency of 85%. The compressor runs at 500 r.p.m. The refrigerant is
Fig. 14.27
p
h
2
4 30°C 3
(^1) Evap.
Cont.
Th.
- 15°C Comp.