910 ENGINEERING THERMODYNAMICS
dharm
\M-therm\Comp1.pm5
- Four processes of a thermodynamic cycle are shown above in Fig. 11 on the T-s plane in the
sequence 1—2—3—4. The corresponding correct sequence of these processes in the p-V
plane as shown in Fig. 12 will be
3
4
1
2
T
s
T
A
D
C
B
V
Fig. 11 Fig. 12
(a) (C—D—A—B)(b) (D—A—B—C)
(c) (A—B—C—D)(d) (B—C—D—A).
- The Fig. 13 shows an isometric cooling process
1-2 of a pure substance. The ordinate and
abscissa are respectively
(a) pressure and volume
(b) enthalpy and entropy
(c) temperature and entropy
(d) pressure and enthalpy. - For a thermodynamic cycle to be irreversible,
it is necessary that
(a)
δQ
T
z =^0 (b) δQ
T
z <^0
(c) δQ
T
z >^0 (d) δQ
T
z ≥^0.
- Neglecting changes in kinetic energy and potential energy, for unit mass the availability in
a non-flow process becomes a = φ – φ 0 where φ is the availability function of the
(a) open system (b) closed system
(c) isolated system (d) steady flow process. - It can be shown that for a simple compressible substance, the relationship
cc TV
T
p
p v PTv
−= F
HG
I
KJ
F
HG
I
KJ
- ∂
∂
∂
∂
2
exists
where cp and cv are specific heats at constant pressure and constant volume respectively, T
is temperature, V is volume and p is pressure.
Which one of the following statements is NOT true?
(a) cp is always greater than cv
(b) The right side of the equation reduces to R for an ideal gas
1
2
Fig. 13