10.9 CYLINDRICAL AND SPHERICAL POLAR COORDINATES
xyzrijkO
θP
ˆer
ˆeφˆeθφFigure 10.9 Spherical polar coordinatesr, θ, φ.Substituting these relations and (10.44) into the expression forawe find
a=zρsinφ(cosφˆeρ−sinφˆeφ)−ρsinφ(sinφˆeρ+cosφˆeφ)+z^2 ρcosφˆez
=(zρsinφcosφ−ρsin^2 φ)ˆeρ−(zρsin^2 φ+ρsinφcosφ)ˆeφ+z^2 ρcosφeˆz.Substituting into the expression for∇·agiven in table 10.2,
∇·a=2zsinφcosφ−2sin^2 φ− 2 zsinφcosφ−cos^2 φ+sin^2 φ+2zρcosφ
=2zρcosφ− 1.
Alternatively, and much more quickly in this case, we can calculate the divergence
directly in Cartesian coordinates. We obtain
∇·a=∂ax
∂x+
∂ay
∂y+
∂az
∂z=2zx− 1 ,which on substitutingx=ρcosφyields the same result as the calculation in cylindrical
polars.
Finally, we note that similar results can be obtained for (two-dimensional)polar coordinates in a plane by omitting thez-dependence. For example, (ds)^2 =
(dρ)^2 +ρ^2 (dφ)^2 , while the element of volume is replaced by the element of area
dA=ρdρdφ.
10.9.2 Spherical polar coordinatesAs shown in figure 10.9, the position of a point in spaceP, with Cartesian
coordinatesx, y, z, may be expressed in terms of spherical polar coordinates
r, θ, φ,where
x=rsinθcosφ, y=rsinθsinφ, z=rcosθ, (10.53)