Mathematical Methods for Physics and Engineering : A Comprehensive Guide

(Darren Dugan) #1

LINE, SURFACE AND VOLUME INTEGRALS


Substituting this into (11.26) and takingcout of both integrals because it is constant, we
find




S

dS×∇φ=c·


C

φdr.

Sincecis an arbitrary constant vector we therefore obtain the stated result (11.24).


Equation (11.25) may be proved in a similar way, by lettinga=b×cin Stokes’

theorem, wherecis again a constant vector. We also note that by settingb=r


in (11.25) we find


S

(dS×∇)×r=


C

dr×r.

Expanding out the integrand on the LHS gives


(dS×∇)×r=dS−dS(∇·r)=dS− 3 dS=− 2 dS.

Therefore, as we found in subsection 11.5.2, the vector area of an open surfaceS


is given by


S=


S

dS=

1
2


C

r×dr.

11.9.2 Physical applications of Stokes’ theorem

Like the divergence theorem, Stokes’ theorem is useful in converting integral


equations into differential equations.


From Amp`ere’s law, derive Maxwell’s equation in the case where the currents are steady,
i.e.∇×B−μ 0 J= 0.

Ampere’s rule for a distributed current with current density` Jis


C

B·dr=μ 0


S

J·dS,

for any circuitCbounding a surfaceS. Using Stokes’ theorem, the LHS can be transformed
into



S(∇×B)·dS; hence ∫

S

(∇×B−μ 0 J)·dS=0

foranysurfaceS. This can only be so if∇×B−μ 0 J= 0 , which is the required relation.
Similarly, from Faraday’s law of electromagnetic induction we can derive Maxwell’s
equation∇×E=−∂B/∂t.


In subsection 11.8.3 we discussed the flow of an incompressible fluid in the

presence of several sources and sinks. Let us now considervortexflow in an


incompressible fluid with a velocity field


v=

1
ρ

eˆφ,

in cylindrical polar coordinatesρ, φ, z. For this velocity field∇×vequals zero

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