Mathematical Methods for Physics and Engineering : A Comprehensive Guide

(Darren Dugan) #1

APPLICATIONS OF COMPLEX VARIABLES


exp[±iφ(z) ] will be purely real. What is more, one such factor, known as the


dominantterm, will be exponentially large, whilst the other (thesubdominantterm)


will be exponentially small. AStokes lineis precisely where this happens.


We can now see how the change takes place without an observable discontinuity

occurring. Suppose thaty 1 (z) is very large andy 2 (z) is very small on a Stokes line.


Then a finite change inA 2 will have a negligible effect onY(z); in fact, Stokes


showed, for some particular cases, that the change is less than the uncertainty


iny 1 (z) arising from the approximations made in deriving it. Since the solution


with any particular asymptotic form is determined in a region bounded by two


Stokes lines to within an overall multiplicative constant and the original equation


is linear, the change inA 2 when one of the Stokes lines is crossed must be


proportional toA 1 ,i.e.A 2 changes toA 2 +SA 1 ,whereSis a constant (theStokes


constant) characteristic of the particular line but independent ofA 1 andA 2 .It


should be emphasised that, at a Stokes line, if the dominant term is not present


in a solution, then the multiplicative constant in the subdominant termcannot


change as the line is crossed.


As an example, consider the Bessel functionJ 0 (z)ofzeroorder.Itissingle-

valued, differentiable everywhere, and can be written as a series in powers ofz^2 .It


is therefore an integral even function ofz. However, its asymptotic approximations


for two regions of thez-plane, Rez>0andzreal and negative, are given by


J 0 (z)∼

1

2 π

1

z

(
eize−iπ/^4 +e−izeiπ/^4

)
, |arg(z)|<^12 π,|arg(z−^1 /^2 )|<^14 π,

J 0 (z)∼

1

2 π

1

z

(
eize^3 iπ/^4 +e−izeiπ/^4

)
, arg(z)=π,arg(z−^1 /^2 )=−^12 π.

We note in passing that neither of these expressions is naturally single-valued,


and a prescription for taking the square root has to be given. Equally, neither is


an even function ofz. For our present purpose the important point to note is


that, for both expressions, on the line argz=π/2 bothz-dependent exponents


become real. For large|z|the second term in each expression is large; this is the


dominant term, and its multiplying constanteiπ/^4 is the same in both expressions.


Contrarywise, the first term in each expression is small, and its multiplying


constant does change, frome−iπ/^4 toe^3 iπ/^4 ,asargzpasses throughπ/2 whilst


increasing from 0 toπ. It is straightforward to calculate the Stokes constant for


this Stokes line as follows:


S=

A 2 (new)−A 2 (old)
A 1

=

e^3 iπ/^4 −e−iπ/^4
eiπ/^4

=eiπ/^2 −e−iπ/^2 =2i.

If we had moved (in the negative sense) from argz= 0 to argz=−π, the relevant


Stokes line would have been argz=−π/2. There the first term in each expression


is dominant, and it would have been the constanteiπ/^4 in the second term that


would have changed. The final argument ofz−^1 /^2 would have been +π/2.

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