FAULT CALCULATIONS AND STABILITY STUDIES 281The contribution from the lower voltage motors is found as follows.
The average ratio of starting current to rated current (Is/In) for the lower voltage motors may be
assumedtobe,
Is
In
= 6 .5 pu for lower voltage motorsTheir sub-transient impedanceZlm′′ is
Z′′lm=1. 0
6. 5
= 0 .153 pu(atSlm)Typical lower voltage motors have a starting power factor of between 0.25 and 0.35 lagging,
hence assume 0.35.
The sub-transient impedanceZlm′′ of the motors becomes,
Z′′lm= 0. 054 +j 0 .143 puThe equivalent impedanceZtdof the distribution transformers can be found by the method in
sub-section 11.5.2.5 or taken as,
Ztd= 0. 0 +j 0 .055 pu(atStd)Again assume that the air-gap emfElm′′ is 1.0 pu.
The contributionIlm′′ from the lower voltage motors is,
Ilm′′ =Elm′′
(
Z′′lm
Slm+
Ztd
2 Ktd(Slm+Sls))
Sbase=
1. 0 Slm
(
0. 054 +j 0. 143 +j 0. 06
Ktd2)
Sbase(11.3)
Where
Ktd2= 2 Ktd(
1. 0 +
Sls
Slm)
The total sub-transient symmetrical rms fault currentIfrms′′ is,
Ifrms′′ =Ig′′+Ihm′′ +Ilm′′ ( 11. 4 )11.6.1 Calculate the sub-transient peak fault current contributions
Many power system networks can be reduced to a simple series-connected circuit containing a resis-
tanceRand an inductanceL, for the purpose of calculating the transient fault current. Furthermore a