FAULT CALCULATIONS AND STABILITY STUDIES 289
Hence
Pload=Phm1+Phm2+Plm+Phs+Pls
=90.0 MW
Qhm1=19.84 MVAr,Qhm2=14.17 MVAr
Qlm=3.10 MVAr,Qhs=13.65 MVAr
Qls=0.5 MVAr
Qload=(Qhm1+Qhm2+Qlm+Qhs+Qls) 1. 015
= 52. 03
Sload=
√
(Pload^2 +Qload^2 )= 103 .96 MVA
The operating power factor PFloadis,
PFload=
Pload
Sload
=
90. 0
103. 96
=0.8657 lagging
The generator MVA isSgenwhich equals 37.5.
Choose the base MVA to beSbase=100.
Assume all five generators are operating when the three-phase zero impedance fault occurs.
Calculate the rms symmetrical fault currents for the generators and each type of load.
a) The generators and unit transformers
Ig′′=
5 × 1. 1 × 34. 0
j
(
0. 13 +
0. 08
1. 25
)
100. 0
= 0. 0 −j 9 .639 pu
- The high voltage motors and unit transformers.
These consist of two groupsShm1andShm2, let their total beShm.
Ihm′′ =
1. 0 ×( 40. 23 + 28. 74 )
(
0. 033 +j 0. 164 +
j 0. 06
1. 10
)
100. 0
=
0. 6897
0. 033 +j 0. 164 +j 0. 0545
= 14. 1184 ( 0. 033 −j 0. 2185 )
= 0. 4659 −j 3 .0849 pu
- The high voltage variable speed drive motors.
These can be ignored as sources of sub-transient current.