562 HANDBOOK OF ELECTRICAL ENGINEERING
Convert to system base values.SWBD load kVA=Sog=SWBD load power
SWBD load power factor=Pog
cosφog=
900 × 1000
0. 9
= 1000 × 103 VA
SWBD load kVA/phase=Sogp=1000 × 1000
3
= 333 × 103 VA
SWBD load power/phase=Pogp=900 × 1000
3
= 300 × 103 VA
SWBD load reactive power/phase=Qogp=√
(Sogp^2 −Sogp^2 )= 145. 29 × 103 VArOhmic resistance per phase=Rogp=(
Phase voltage
Phase active power) 2
=
(
Vog
Pogp) 2
=
13 , 800 × 13 , 800
3 × 300 × 103
× 106
= 211 .6 ohms per phaseOhmic reactance per phase=Xogp=(
Phase voltage
Phase reactive power) 2
=
(
Vog
Qogp) 2
=
13 , 800 × 13 , 800
3 × 145. 29 × 103
× 106
= 436 .92 ohms per phaseConvert to the system base impedance values.System impedance in per-unit=Ohmic impedance=(load base kVA) (system base kVA)
(system base voltage)^2 (load base kVA)Hence
Rog=( 211. 6 × 1000 × 1000 )( 3125 × 1000 )
( 13 , 800 )^2 ( 1000 × 1000 )
= 3 .4722 puAnd
Xog=( 436. 92 × 1000 × 1000 )( 3125 × 1000 )
( 13 , 800 )^2 ( 1000 × 1000 )
= 7 .1696 puThese are the parallel elements of the load in per-unit at the system base.e) Motor control centre (MCC) parallel circuit components.