r
x
y
q
We have
x^2 +y^2 =r^2
Dividing byr^2 gives
(x
r
) 2
+
(y
r
) 2
= 1
or cos^2 θ+sin^2 θ= 1
Thisidentity should definitely become second nature to you – it is absolutely vital. By
dividing through by cos^2 θwe get 1+tan^2 θ=sec^2 θand dividing through by sin^2 θgives
cot^2 θ+ 1 =cosec^2 θ, so there is no need to remember all three identities.
Solution to review question 6.1.6
(i) Using cos^2 θ+sin^2 θ=1wehave
cos^2 θ= 1 −sin^2 θ= 1 −
1
49
=
48
49
so
cosθ=
√
48
49
in first quadrant
=
4
√
3
7
Then tanθ=
sinθ
cosθ
=
1 / 7
4
√
3 / 7
=
1
4
√
3
(ii) sinθ=
√
1 −cos^2 θ=
√
1 −
1
3
=
√
2
3
tanθ=
√ 2 3 1 √ 3
=
√
2
(iii) sec^2 θ=
1
cos^2 θ
= 1 +tan^2 θ
= 1 +
(
1
√
2
) 2
=
3
2