As usual, the places where you might have trouble occur when negative
signs and fractions are involved. In such cases, just take it steady and
check each step.
(i)
∫
3 dx= 3
∫
dx= 3 x+C
(ii)
∫
2
x^2
dx= 2
∫
x−^2 dx= 2
x−^2 +^1
− 2 + 1
+C= 2
x−^1
− 1
+C=−
2
x
+C
(iii)
∫
√
xdx=
∫
x
1
(^2) dx=
x
1
2 +^1
1
2 +^1
+C=
x^3 /^2
3 / 2
+C=
2
3
x^3 /^2 +C
(iv)
∫
x
1
(^3) dx=
x
1
3 +^1
1
3 +^1
+C=
x^4 /^3
4 / 3
+C=
3
4
x^4 /^3 +C
B. These are all standard integrals, known because we know what to
differentiate to get them.
(i)
d
dx
(cosx)=−sinx
so
∫
sinxdx=−cosx+C
(ii)
d
dx
(ex)=ex
so
∫
exdx=ex+C
(iii)
d
dx
(ln|x|)=
1
x
so
∫
1
x
dx=ln|x|+C
NB Note that
∫
1
x
dx =
x^0
0
! Also note the reminder about the modulus
in ln|x|.
These and others we can put together in the table of standard integrals
on page 256.
9.2.3 Addition of integrals
➤
251 281➤
If you differentiate a sum then the result is the sum of the derivatives:
d
dx
(f+g)=
df
dx
- dg
dx
Similarly, the integral of a sum is the sum of the integrals:
∫
(f+g)dx=
∫
fdx+
∫
gdx
(not forgetting the arbitrary constant of course).