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2.1. Horner’s Method^51



  1. In applying Horner’s Method, you should not fail to record zero coef-
    ficients. Check that the table for evaluating at t = 6 the polynomial


t5 - 4t3 + 2t2 - 7

is
1 0 -4 2 0 -7
6 36 192 1164 6984

1 6 32 194 1164 6977
and read off the required value of the polynomial. Check the value
independently.


  1. Make up several polynomials of various degrees and evaluate them for
    a number of values of 1. Compare the number of operations required
    in Horner’s Method to the number that would be required for a term-
    by-term evaluation.

  2. Programme a computer to carry out an efficient calculation of the
    value oft = 2.376 of the polynomial


4.82t5 f 87.2433t4 - 764.331t2 + 12.354t + 77.4412.


  1. A student, evaluating a polynomial, presses the following buttons on
    his pocket calculator:


7x6~ x6=-2= x6=-3=x6=+1= x6=+2=

Find the polynomial being evaluated and the point of evaluation.
Determine the value of the polynomial.


  1. Find the polynomial, the point of evaluation and the required value
    of the polynomial from the following table:


3 5 1 -2 6
6 22 46 88

3 11 23 44 94

Check your answer using a pocket calculator.


  1. (a) Verify that


t4 + t2 - 3t + 7 = (t3 + 3t2 + lot + 27)(t - 3) + 88.

(b) Construct the Horner table for evaluating this polynomial at
t = 3. The last entry in the bottom row gives the value sought.
Interpret the remaining entries in the bottom row. Account for
your interpretation.
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