Chapter 5 Induction154
False Claim.Every Fibonacci number is even.
False proof. 1. We use strong induction.
- The induction hypothesis is thatF.n/is even.
- We will first show that this hypothesis holds fornD 0.
- This is true, sinceF.0/D 0 , which is an even number.
- Now, supposen 2. We will show thatF.n/is even, assuming thatF.k/is
even for allk < n. - By assumption, bothF.n 1/andF.n 2/are even.
- Therefore,F.n/is even, sinceF.n/DF.n 1/CF.n 2/and the sum of
two even numbers is even. - Thus, the strong induction principle implies thatF.n/is even for alln > 0.
Problem 5.19.
ThenthFibonacci number,F.n/, is defined as follows
F.0/WWD0; (5.19)
F.1/WWD1; (5.20)
F.n/WWDF.n 1/CF.n 2/ forn > 1: (5.21)
Indicate exactly which sentence(s) in the following bogus proof contain logical
errors? Explain.
False Claim.Every Fibonacci number is even.
Bogus proof.Let all the variablesn;m;kmentioned below be nonnegative integer
valued. Let Even.n/mean thatF.n/is even. The proof is by strong induction with
induction hypothesis Even.n/.
base case:F.0/D 0 is an even number, so Even.0/is true.
inductive step: We assume may assume the strong induction hypothesis
Even.k/for 0 kn;
and we must prove Even.nC1/.