Chapter 2 The Well Ordering Principle34
So supposeS.m 10/holds. Then 5 j.m 10/, because...
But if 5 j.m 10/, then obviously 5 jm, contradicting the fact thatm
is a counterexample.
Next, ifS.m 15/holds, we arrive at a contradiction in the same way.
Since we get a contradiction in both cases, we conclude that...
which proves that (2.2) holds.
Problem 2.2.
TheFibonacci numbersF.0/;F.1/;F.2/;:::are defined as follows:
F.0/WWD0;
F.1/WWD1;
F.n/WWDF.n 1/CF.n 2/ forn2: (2.3)
Exactly which sentence(s) in the following bogus proof contain logical errors?
Explain.
False Claim.Every Fibonacci number is even.
Bogus proof.Let all the variablesn;m;kmentioned below be nonnegative integer
valued.
- The proof is by the WOP.
- Let Even.n/mean thatF.n/is even.
- LetCbe the set of counterexamples to the assertion that Even.n/holds for
alln 2 N, namely,
CWWDfn 2 NjNOT.Even.n//g:
- We prove by contradiction thatCis empty. So assume thatCis not empty.
- By WOP, there is a least nonnegative integer,m 2 C,
- Thenm > 0, sinceF.0/D 0 is an even number.
- Sincemis the minimum counterexample,F.k/is even for allk < m.
- In particular,F.m 1/andF.m 2/are both even.