192 CHAPTER 4. JUNCTIONS IN SEMICONDUCTORS:P-NDIODES
Vin VO
Input Output
C
Vx IL L
Time
Vx
Inductor
currentT
ton toff
(a)
(b)
Figure 4.28: (a)Buck converter schematic (b) Voltage and current changesOFF timeVx=0. Thus in steady state
if−ii=0=∫tON0(Vin−Vo)dt+∫tON+tOFFtON(−Vo)dt (4.8.17)which gives
(Vin−Vo)tON−VotOFF=0 (4.8.18)
or
Vo
Vin
=
tON
T(4.8.19)
Using D as the “duty cycle” gives
D=tON
T(4.8.20)
the voltage relationship becomesVo=DVin. Since the circuit is ’lossless’ and the input
and output powers must match on the averageVoIo=VinIin. This requires the diode to