Part I Proofs
Bogus proof.
aDb
a^2 Dab
a^2 b^2 Dab b^2
.a b/.aCb/D.a b/b
aCbDb
aD0:Problem 0.2.
It’s a fact that the Arithmetic Mean is at least as large the Geometric Mean, namely,
aCb
2p
abfor all nonnegative real numbersaandb. But there’s something objectionable
about the following proof of this fact. What’s the objection, and how would you fix
it?
Bogus proof.
aCb
2‹
p
ab; soaCb‹
2p
ab; soa^2 C2abCb^2‹
4ab; soa^2 2abCb^2‹
0; so
.a b/^2 0 which we know is true.The last statement is true becausea bis a real number, and the square of a real
number is never negative. This proves the claim.
Problem 0.3.
Albert announces to his class that he plans to surprise them with a quiz sometime
next week.