392 Nonlinear Programming III: Constrained Optimization Techniques
subject to
− 2 ≤x 1 ≤ 2
− 2 ≤x 2 ≤ 2 (E 1 )
Thesolution of this problem can be obtained as
X=
[
− 2
2
]
withf (X)= − 4
Step 4: Since we have solved one LP problem, we can take
Xi+ 1 =X 2 =
{
− 2
2
}
Step 5:Sinceg 1 (X 2 ) = 23 >ε, we linearizeg 1 ( X)about pointX 2 as
g 1 (X)≃g 1 (X 2 ) +∇g 1 (X 2 )T(X−X 2 )≤ 0 (E 2 )
As
g 1 (X 2 ) = 23 ,
∂g 1
∂x 1
∣
∣
∣
∣
X 2
=( 6 x 1 − 2 x 2 )|X 2 =− 16
∂g 1
∂x 2
∣
∣
∣
∣
X 2
=(− 2 x 1 + 2 x 2 )|X 2 = 8
Eq. (E 2 ) becomes
g 1 ( X)≃− 16 x 1 + 8 x 2 − 52 ≤ 0
By adding this constraint to the previous LP problem, the new LP prob-
lem becomes
Minimizef=x 1 −x 2
subject to
− 2 ≤x 1 ≤ 2
− 2 ≤x 2 ≤ 2 (E 3 )
− 16 x 1 + 8 x 2 − 52 ≤ 0
Step 6: Set the iteration number asi=2 and go to step 4.
Step 4: Solve the approximating LP problem stated in Eqs. (E 3 ) and obtain the
solution
X 3 =
{
− 0. 5625
2. 0
}
withf 3 = f(X 3 ) =− 2. 5625
This procedure is continued until the specified convergence criterion,
g 1 (Xi) ≤ε,in step 5 is satisfied. The computational results are summa-
rized in Table 7.2.