502 Geometric Programming
In this section we prove thatf∗=v∗ and also thatf∗corresponds to the global
minimum off (X). For convenience of notation, let us denote the objective function
f (X)byx 0 and make the exponential transformation
ewi=xi or wi= nl xi, i= 0 , 1 , 2 ,... , n (8.30)where the variableswi are unrestricted in sign. Define the new variablesj, also
termedweights, asj=Uj
x 0=
cj∏n
i= 1x
aij
ix 0, j= 1 , 2 ,... , N (8.31)which can be seen to be positive and satisfy the relation∑Nj= 1j= 1 (8.32)By taking logarithms on both sides of Eq. (8.31), we obtainlnj= nl cj+∑ni= 1aijlnxi− nl x 0 (8.33)orlnj
cj=
∑ni= 1aijwi−w 0 , j= 1 , 2 ,... , N (8.34)Thus the original problem of minimizingf (X)with no constraints can be replaced
by one of minimizingw 0 subject to the equality constraints given by Eqs. (8.32) and
(8.34). The objective functionx 0 is given byx 0 =ew^0 =∑N
j= 1cj∏ni= 1eaijwi=
∑N
j= 1cje∑n
i= 1 aijwi (8.35)Since the exponential function (eaijwi) is convex with respect towi, the objective
functionx 0 , which is a positive combination of exponential functions, is also convex
(see Problem 8.15). Hence there is only one stationary point forx 0 and it must be the
global minimum. The global minimum point ofw 0 can be obtained by constructing the
following Lagrangian function and finding its stationary point:L(w,,λ)=w 0 +λ 0(N
∑
i= 1i− 1)
+
∑N
j= 1λj(n
∑i= 1aijwi−w 0 − nlj
cj