502 Geometric Programming
In this section we prove thatf∗=v∗ and also thatf∗corresponds to the global
minimum off (X). For convenience of notation, let us denote the objective function
f (X)byx 0 and make the exponential transformation
ewi=xi or wi= nl xi, i= 0 , 1 , 2 ,... , n (8.30)
where the variableswi are unrestricted in sign. Define the new variablesj, also
termedweights, as
j=
Uj
x 0
=
cj
∏n
i= 1
x
aij
i
x 0
, j= 1 , 2 ,... , N (8.31)
which can be seen to be positive and satisfy the relation
∑N
j= 1
j= 1 (8.32)
By taking logarithms on both sides of Eq. (8.31), we obtain
lnj= nl cj+
∑n
i= 1
aijlnxi− nl x 0 (8.33)
or
ln
j
cj
=
∑n
i= 1
aijwi−w 0 , j= 1 , 2 ,... , N (8.34)
Thus the original problem of minimizingf (X)with no constraints can be replaced
by one of minimizingw 0 subject to the equality constraints given by Eqs. (8.32) and
(8.34). The objective functionx 0 is given by
x 0 =ew^0 =
∑N
j= 1
cj
∏n
i= 1
eaijwi
=
∑N
j= 1
cje
∑n
i= 1 aijwi (8.35)
Since the exponential function (eaijwi) is convex with respect towi, the objective
functionx 0 , which is a positive combination of exponential functions, is also convex
(see Problem 8.15). Hence there is only one stationary point forx 0 and it must be the
global minimum. The global minimum point ofw 0 can be obtained by constructing the
following Lagrangian function and finding its stationary point:
L(w,,λ)=w 0 +λ 0
(N
∑
i= 1
i− 1
)
+
∑N
j= 1
λj
(n
∑
i= 1
aijwi−w 0 − nl
j
cj