Problems 47Figure 1.15 Two-bar truss.1.2 The two-bar truss shown in Fig. 1.15 is symmetric about theyaxis. The nondimensional
area of cross section of the membersA/Aref, and the nondimensional position of joints
1 and 2,x/ h, are treated as the design variablesx 1 andx 2 , respectively, whereAref
is the reference value of the area(A)andhis the height of the truss. The coordinates
of joint 3 are held constant. The weight of the truss(f 1 )and the total displacement of
joint 3 under the given load(f 2 )are to be minimized without exceeding the permissible
stress,σ 0. The weight of the truss and the displacement of joint 3 can be expressed asf 1 (X)= 2 ρhx 2√
1 +x 12 Areff 2 (X)=P h( 1 +x^21 )^1.^5√
1 +x^41
2√
2 Ex 12 x 2 Aref
whereρis the weight density,Pthe applied load, andEthe Young’s modulus. The
stresses induced in members 1 and 2 (σ 1 andσ 2 ) are given byσ 1 (X)=P ( 1 +x 1 )√
( 1 +x 12 )
2√
2 x 1 x 2 Arefσ 2 (X)=P (x 1 − 1 )√
( 1 +x 12 )
2√
2 x 1 x 2 Aref
In addition, upper and lower bounds are placed on design variablesx 1 andx 2 asximin≤xi≤ximax; i= 1 , 2Find the solution of the problem using a graphical method with (a)f 1 as the objective, (b)f 2
as the objective, and (c) (f 1 +f 2 ) as the objective for the following data:E= 30 × 106 psi,