MATHEMATICS AND ORIGAMI

Mathematics and Origami

10. Fold 5 to get
    7

2

a= which in turn produces

7

1

11. Copy and rotate 5 to get 6 which shows
    7

1

x=

12. That square 6 is set apart in fig 4, displaying
    7

1

x= ; by folding, we get

4

1

8

2

a= =

13. Finally, folding over
    4

1

, we get

2

1

(within the ellipse).

Till now we have gone the reverse way: we began with
37

1

to arrive to

2

1

. Therefore the di-

rect way will be the reverse of the reverse, beginning with
2

1

:

1 Get
2

1

,

8

2

4

1

= on the left side of 6.

2 Fold 6 in such a way that its right lower vertex lies on upper side while the lower side lies

on

8

2

a=. So we get

7

1

x=.

3. Copy 6 in 5 rotating 90º anticlockwise.


4. In 5, fold
   7

1

to get

7

2

a= on left side.

5. Fold square 5 in such a manner that its right lower vertex lies on upper side while lower

side lies on

7

2

a=. So we get

6

1

x=.

6. Copy 5 in 4 rotating it 90º anticlockwise.

11

10

1

1 37

6

6

1

1

19

7

1

1

2

8

1

4

2

(^14)