MATHEMATICS AND ORIGAMI

Mathematics and Origami

2

BDtgB

CO= ; LH=HD=LB

HD

x

senB=

()CO x

x

B

−

=

2

cos

2

tg

LH

CO x

B

−

=

x= 2 COcosB− 2 xcosB ;

B

CO B

x

1 2 cos

2 cos

+

=

5- ∆LHG = ∆DHG by symmetry

Ang. CHG = Ang. CHL + Ang. LHG = 108 º

2

90

2

180

= + =

−

+

B B

B

K D K D

B

F

E

C

B F

D

C

B

OO

B O G D

L H

C

B G D

L

C

H

B G

L

C

H

K D

B F

L

C

H L

E

O

M

C

H

G

(^123)
(^45)
(^678)
M
paralelas
x