Jesús de la Peña Hernández
As said at the beginning, square side is 1, so we must ignore the first root for it ́s greater
than 1. Therefore, it is:
k = 2 − 1Let ́s see the value we get for DF:2 1
22 1(^12) = −
−
DF= −
i.e. DF = k what means that the octagon is coherent with the folding process.
10.5 ENNEAGON
The present solution has been chosen as the best among several others, but nevertheless
it results imperfect.
Justification (EA = 1):
In ∆OAB
GIVEN OBTAINED
8
1
AB= Ang. BOA = 8,1301024º
2
1
OA=
Ang. BAO = 45º
C
E
D
B
O
F A
C
E
D F
A
E
G
O
A
G
A
E
O
AB = AG / 4B B
A
D
E
O
E
D
A
12 34
C